A mixture of He and Ne at a total pressure of 0.95 atm is found to contain 0.32 mol of He and 0.56 mol of Ne. The partial pressure of Ne is ________ atm.

Respuesta :

Answer:

Partial pressure of Ne is 0.61 atm.

Explanation:

Mole fraction of a gas [tex](x)[/tex] in mixture = (no. of moles of the gas in mixture)/(total no. of moles of gases in mixture)

Here, total no. of moles of gases = (0.32 + 0.56) moles = 0.88 moles

So, mole fraction of Ne in mixture, [tex]x_{Ne}=\frac{0.56}{0.88}=0.64[/tex]

Let's assume both He and Ne along with their mixture behaves ideally,

Hence, in accordance with Dalton's law of partial pressure-

                     [tex]P_{Ne}=x_{Ne}\times P_{total}[/tex]

Where, [tex]P_{Ne}[/tex] and [tex]P_{total}[/tex] are partial pressure of Ne and total pressure respectively.

So,  [tex]P_{Ne}=(0.64)\times (0.95atm)=0.61atm[/tex]

So, partial pressure of Ne is 0.61 atm.