A 9.79 mol sample of freon gas was placed in a balloon. Adding 3.50 mol of freon gas to the balloon increased its volume to 21.8 L. What was the initial volume of the balloon?

Respuesta :

Answer:

16.06 L was the initial volume of the balloon.

Explanation:

Initial moles of freon in ballon = [tex]n_1=9.79 mol[/tex]

Initial volume of freon gas in ballon = [tex]V_1=?[/tex]

Moles of freon gas added in the balloon = n = 3.50 mole

Final moles of freon in ballon = [tex]n_2=n_1+n=9.79 mol+3.50 mol=13.29 mol[/tex]

Final volume of freon gas in ballon = [tex]V_2=21.8 L[/tex]

Using Avogadro's law:

[tex]\frac{V_1}{n_1}=\frac{V_2}{n_2}[/tex] ( at constant pressure and temperature)

[tex]V_1=\frac{V_2\times n_1}{n_2}=\frac{21.8 L\times 9.79 mol}{13.29 mol}=16.06L[/tex]

16.06 L was the initial volume of the balloon.