Explanation:
It is known that the relation between electric field and potential difference between the plates of a parallel plate capacitor is as follows.
E = [tex]\frac{V}{D}[/tex]
So, differentiating this on both the sides with respect o time as follows.
[tex]\frac{dE}{dt} = \frac{1}{D} \frac{dV}{dt}[/tex]
Hence, rate of electric field changes between the plates of parallel plate capacitor as follows.
[tex]\frac{dE}{dt} = \frac{1}{D} \frac{dV}{dt}[/tex]
= [tex]\frac{1}{1.5 \times 10^{-3} m} \times 140 V/s[/tex]
= [tex]93.33 \times 10^{3}[/tex] V/ms
Thus, we can conclude that the rate at which the electric field changes between the round plates of a capacitor is [tex]93.33 \times 10^{3}[/tex] V/ms.
