Answer:
Formula of oxide is [tex]Fe_{2}O_{3}[/tex]
Explanation:
The given compound consists of Fe and O.
So, mass of oxygen in sample = (mass of sample) - (mass of Fe in sample)
= (6.285 g ) - (4.396 g)
= 1.889 g
Molar mass of O = 16 g/mol and molar mass of Fe = 55.845 g/mol
So, ratio of number of moles of Fe and O (Fe : O)
= [tex]\frac{4.396}{55.845}:\frac{1.889}{16}[/tex]
= 0.0787 : 0.118
= [tex]1:\frac{0.118}{0.0787}[/tex]
= 1 : 1.5
= 2 : 3
So, formula of oxide is [tex]Fe_{2}O_{3}[/tex]
