Answer:
677.76 g of oxygen needed.
Explanation:
Given data:
Mass of glucose = 635.2 g
Mass of oxygen needed = ?
Solution:
Chemical equation:
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + energy
Number of moles of glucose:
Number of moles = mass/ molar mass
Number of moles = 635.2 g / 180.156 g/mol
Number of moles = 3.53 mol
Now we will compare the moles of glucose with oxygen.
C₆H₁₂O₆ : O₂
1 : 6
3.53 : 6×3.53 = 21.18 mol
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 21.18 g × 32 g/mol
Mass = 677.76 g
The mass of grams of pure oxygen you need to consume 635.2g of glucose is 677.55 grams
Given the chemical reaction of glucose and oxygen represented as
[tex]C_6H_{12}O_6+6O_2\rightarrow 6CO_2+6H_2O[/tex]
Given the following
Mass of Glucose = 635.2g
Get the molar mass of glucose:
Molar mass of glucose = (6×12) + (1×12) + (6×16)
Molar mass of glucose= 72 + 12 + 96
Molar mass of glucose = 180g/mol
Number of moles of glucose = [tex]\frac{635.2}{180} = 3.52moles[/tex]
Since Glucose reacted with 6 moles of oxygen:
Number of moles of reacted oxygen = 6 × 3.52 = 21.173moles
Find the grams of pure oxygen:
[tex]Mass =Molar \ mass \times moles\\Mass = 32 \times 21.17\\Mass=677.55g[/tex]
Hence the mass of grams of pure oxygen you need to consume 635.2g of glucose is 677.55 grams
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