Answer:3.67,1
Explanation:
TE = (O + 4T + P) / 6
where,
TE = Pert Expected Time Duration,
O = Optimistic estimate, =2
T = Typical estimate,=3
P = Pessimistic estimate=8
TE = (O + 4T + P) / 6
=(2+4*3+8)/6
3.6666=3.67
σ = (P – O)/6
=(8-2)/6
=1
Expected time and variance are 3.67 and 1.
Given that;
Optimistic (to) =2
Most likely (tm) = 3
Pessimistic (tp) = 8
Find:
Expected time and variance
Computation:
[tex]Expected time =\frac{to + 4tm + tp}{6} \\\\Expected time =\frac{2 + 4(3) + 8}{6} \\\\Expected time =\frac{22}{6} \\\\Expected time = 3.67[/tex]
[tex]Variance = \sigma^2 = [\frac{tp - to}{6} ]^2\\\\Variance = \sigma^2 = [\frac{8 - 2}{6} ]^2\\\\Variance = \sigma^2 = 1[/tex]
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