Answer:
public int largest(int[] numbers, int index) {
if (index == 0)
return numbers[0];
return Math.max(numbers[index], largest(numbers, index-1));
}
Step-by-step explanation:
An image of the question is attached. The missing base case is to check for when the index is equals to zero.
if (index == 0)
When index is zero, it return the only element that is present in the array which is numbers[0].
