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Refrigerant 134a enters a compressor with a mass flow rate of 5 kg/s. The working fluid enters the compressor as a saturated vapor at 15ºC and negligible velocity and leaves the compressor at 1400 kPa with an enthalpy of 281.39 kJ/kg and a velocity of 50 m/s. The power of the compressor is measured to be 132.4 kW. Determine the rate of net heat associated with this process in kW (with three significant figures).

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Answer:see the attachment below

Explanation:

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The rate of net heat associated with this process in kW should be -13.775 KW.

Calculation of the rate of net heat:

At the 15 degrees

hg = h1 = 258.37 + 259.46/2 = 258.915 kJ/kg

And, h2 = 281.39 Kj/kg

Now we have to apply the steady flow energy

m(h1+v1^2/2) +  Q= m(hw + v2^2/2) + w

5(258.915 + 0) = Q = 5(281.39 + 50^2/2 * 10^-3) - 132.40

Based on this, Q = -13.775 Kw

Hence, The rate of net heat associated with this process in kW should be -13.775 KW.

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