Answer:
Therefore,
Strength magnetic field at within the Solenoid,
[tex]B =1.05\times 10^{-2}\ T[/tex]
Explanation:
Given:
Turn = N = 1900
length of solenoid = l = 0.54 m
Current, I = 2.5 A
To Find:
Strength magnetic field within the Solenoid,
B = ?
Solution:
If N is the number of turns in the length, the total current through the rectangle is NI. Therefore, Ampere’s law applied to this path gives
[tex]\int {B} \, ds= Bl=\mu_{0}NI[/tex]
Where,
B = Strength of magnetic field
l = Length of solenoid
N = Number of turns
I = Current
[tex]\mu_{0}=Permeability\ in\ free\ space=4\pi\times 10^{-7}\ Tm/A[/tex]
Therefore,
[tex]B =\dfrac{\mu_{0}NI}{l}[/tex]
Substituting the values we get
[tex]B =\dfrac{4\times 3.14\times 10^{-7}\times 1800\times 2.5}{0.54}= 1.05\times 10^{-2}\ T[/tex]
Therefore,
Strength magnetic field at within the Solenoid,
[tex]B = 1.05\times 10^{-2}\ T[/tex]
