Answer:
(a). The fundamental frequency for the pipe is 72.0 Hz.
(b). This pipe is open at both ends.
(c). The length of the pipe is 2.38 m.
Explanation:
Given that,
Frequency f₁= 576 Hz
Frequency f₂ = 648 Hz
Speed of sound = 343 m/s
We need to calculate the length of the pipe
Using formula of frequency
[tex]F_{2}-f_{1}=\dfrac{v}{2l}[/tex]
Put the value into the formula
[tex]648-576=\dfrac{343}{2l}[/tex]
[tex]l=\dfrac{343}{2\times72}[/tex]
[tex]l=2.38\ m[/tex]
(a).We need to calculate the fundamental frequency for the pipe
Using formula of fundamental frequency
[tex]f=\dfrac{v}{2l}[/tex]
Put the value into the formula
[tex]f=\dfrac{343}{2\times2.38}[/tex]
[tex]f=72.0\ Hz[/tex]
This pipe is open at both ends.
Hence, (a). The fundamental frequency for the pipe is 72.0 Hz.
(b). This pipe is open at both ends.
(c). The length of the pipe is 2.38 m.
