Respuesta :
Answer:
Explanation:
- Given the current and voltage, we can find the resistance of the wore via the formula
R = V / I
V = Voltage = 1.5 V
I = Current = 0.40 A
R = 3.75Ω
- Now, from he formula of Resistance in a wire, we know that
R = ρL / A
ρ = Density of Aluminium = 2.710 [tex]g/m^{3}[/tex]
Radius of wire = 0.00031 m³, from the data given
A = Area of Wire = π×r²
A = 3.14159×0.00031
A = 0.00097 m²
- Now, having the complete data, we can find the length of the wire
L = (R*A)/ρ
L = (3.75 * 0.00097) / 2.710
L = 0.0013 meters
Answer:
42 m
Explanation:
From ohm's law,
V = IR............... Equation 1
Where V = Voltage, I = current, R = Resistance.
Make R the subject of the equation
R = V/I............. Equation 2
Given: V = 1.5 V, I = 0.40 A.
Substitute into equation 2
R = 1.5/0.4
R = 3.75 Ω.
But,
R = ρL/A..............Equation 2
Where ρ = resistivity of the aluminum wire, l = length of the wire, A = cross sectional area of the wire.
make L the subject of the equation,
L = RA/ρ..............Equation 3
Given: R = 3.75 Ω,
A = πd²/4, where d = diameter = 0.62 mm = 0.00062 m, π = 3.14
A = 3.14× 0.00062²/4 = 0.000000302 m²
Constant: ρ = 2.65 × 10⁻⁸ Ω·m
Substitute into equation 3
L = 3.75(0.000000302)/(2.65 × 10⁻⁸ )
L = 3.75(3.02×10⁻⁷)/(2.65 × 10⁻⁸)
L = 42.70 m
L = 42 m ( Two significant figures)