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A uniform magnetic field passes through a horizontal circular wire loop at an angle 15.1 ° from the normal to the plane of the loop. The magnitude of the magnetic field is 4.35 T , and the radius of the wire loop is 0.280 m . Find the magnetic flux Φ through the loop.

Respuesta :

Answer:

Magnetic flux through the loop is 1.03 T m²

Explanation:

Given:

Magnetic field, B = 4.35 T

Radius of the circular loop, r = 0.280 m

Angle between circular loop and magnetic field, θ = 15.1⁰

Magnetic flux is determine by the relation:

[tex]\Phi = BA\cos \theta[/tex]   ....(1)

Here A represents area of the circular loop.

Area of circular loop, A = πr²

Hence, the equation (1) becomes:

[tex]\Phi=B\pi r^{2} \cos \theta[/tex]

Substitute the suitable values in the above equation.

[tex]\Phi=4.35\times\pi (0.28)^{2} \cos 15.1[/tex]

[tex]\Phi[/tex] = 1.03 T m²

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