We want to find one of the roots of a cubic equation given by 1 0 3 x + x − = which is between 0 and 1 by an iterative method. Modify the equation above to 2 1 1 x x + = Start with an appropriate initial value and do the iteration above until it is convergent. For example, 0.8, 1 0.5 1 0.5 , 0 1 2 = + x = x = 0.609, 1 0.8 1 2 2 = + x = 0.728,  1 0.609 1 3 2 = + x = The simplest (minimum) code may look like: