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Enter your answer in the provided box.The following reactions have the indicated equilibrium constants at a particular temperature:N2(g)+ O2(g)⇌ 2NO(g)Kc = 8.3 ×10−252NO(g)+ O2(g)⇌ 2NO2(g)Kc = 6.4 ×109Determine the value of the equilibrium constant for the following equation at the same temperature:2NO(g)⇌ N2(g)+ O2(g)

Respuesta :

Answer:

[tex]k_c_3[/tex]=1.21*[tex]10^{24}[/tex]

Explanation:

[tex]N_2+O_2 = 2NO K_c_1=8.3*10^-25[/tex]...................1

[tex]2NO+O_2 = 2NO_2 K_c2 =6.4*10^9[/tex]………..2

[tex]2NO=N_2+O_2 K_c_3[/tex]=? ………………………3

From the given reaction  

Equation third is reverse reaction of first reaction

Hence [tex]K_c_3=1/K_c_1[/tex]

[tex]K_c_3=1/(8.3*10^-25)[/tex]

[tex]k_c_3[/tex]=1.21*[tex]10^{24}[/tex]

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