Answer:
[tex]v_{f}\approx 4.081\,\frac{m}{s}[/tex]
Explanation:
The final speed of the lander is described by an uniformly accelerated motion, which is described herein:
[tex]v_{f} = \sqrt{(0.8\,\frac{m}{s} )^{2}+2\cdot (1.6\,\frac{m}{s^{2}} )\cdot (197\,in)\cdot (\frac{0.0254\,m}{1\,in} )}[/tex]
[tex]v_{f}\approx 4.081\,\frac{m}{s}[/tex]