A wire of length L and diameter D has a resistance R.
If BOTH the length and the diameter of the same wire are decreased to half of their original values, the resistivity of the new wire:

A. doubles.
B. drops to half its original value.
C. quadruples
D. drops to one quarter its original value.
E. remains the same.

Respuesta :

There seems to be a typo in the question. The question asks to find the resistivity, instead of resistance. Resistivity is a property of the wire and does not change when its physical dimensions change.

Answer:

(A) doubles

Explanation:

The resistivity of a wire is defined by

[tex]\rho=\dfrac{RA}{l}[/tex]

R is the resistance, A is the cross-sectional area and l is the length of the wire.

[tex]R = \dfrac{\rho l}{A}[/tex]

It follows that

[tex]R\propto\dfrac{l}{A}[/tex]

Assuming a circular cross section, the area is given by

[tex]A =\pi \dfrac{D^2}{4}[/tex]

where D is the diameter.

Then

[tex]R\propto\dfrac{l}{D^2}[/tex]

[tex]R=k\dfrac{l}{D^2}[/tex]

k is an arbitrary constant

When l and D are halved, the new resistance, R1 is

[tex]R_1=k\dfrac{0. 5l}{(0.5D)^2} =2k\dfrac{l}{D^2} = 2R[/tex]

Hence, the resistance is doubled.