Respuesta :
Ozone contains three atoms of oxygen and is a very reactive gas. The balanced chemical equation is [tex]\rm 2KI + O_{3} + H_{2}O \rightarrow I_{2} + O_{2} + 2KOH[/tex] and the ozone concentration is 0.246 ppb.
What are ozone and its concentration?
Ozone is found in the atmosphere of the earth and highly reactive gas that contains three atoms of oxygen.
The balanced chemical reaction of the ozone with aqueous potassium iodide can be written as:
[tex]\rm 2KI + O_{3} + H_{2}O \rightarrow I_{2} + O_{2} + 2KOH[/tex]
The concentration of the ozone can be calculated as:
Calculate the moles of potassium iodide as:
Given,
- Mass of KI = [tex]17 \times 10 ^{-6} \;\rm g[/tex]
- Molar mass = 166 g/mol
[tex]\begin{aligned}\rm Moles &= \dfrac{\rm mass}{\rm molar\; mass}\\\\&= \dfrac{17 \times 10 ^{-6} \;\rm g}{166}\\\\&=1.02 \times 10^{-7} \;\rm moles\end{aligned}[/tex]
From the balanced reaction:
If 2 moles of KI reacts with 1 mole of ozone
Then, [tex]1.02 \times 10^{-7}[/tex] moles will react with [tex]5.12 \times 10^{-8}[/tex] moles
Calculate the mass of the ozone that reacted:
[tex]\begin{aligned}\rm Mass &= \rm moles \times molar \;mass\\\\&= 5.12 \times 10^{-8} \times 48\\\\&= 2.46 \times 10^{-6}\;\rm g\end{aligned}[/tex]
Calculate the concentration of the ozone in ppb:
[tex]\rm \text{Concentration in ppb} = \dfrac{(\rm Mass \;of \;solute \;in \;\mu g)}{(volume \;of \;solution \;in \;L)}[/tex]
Given,
- Mass of solute = Mass of Ozone= 2.46 μg
- Volume of solution = 10.0 L
Substituting values in the above reaction:
[tex]\begin{aligned}\rm \text{Concentration in ppb} &= \dfrac{2.46}{10}\\\\&=0.246 \;\rm ppb\end{aligned}[/tex]
Therefore, 0.246 ppb is the concentration of the ozone.
Learn more about ozone here:
https://brainly.com/question/1742464
