Respuesta :
Answer:
Part a: The value of Y_A and Y_B are [tex]\dfrac{\bar{u}_A}{x}[/tex] and [tex]100-x-\dfrac{\bar{u}_A}{x}[/tex] respectively.
Part b: Y_A and Y_B are given as [tex]\dfrac{\bar{u}_A}{50}[/tex] and [tex]50-\dfrac{\bar{u}_A}{50}[/tex] respectively for maximization of Y_B
Part c: The condition for the Pareto efficient allocation is Y_A=Y_B
As the value of Y_A and Y_B are not equal in part 2 thus the condition is not Pareto efficient
Explanation:
Part a
For the value of the utility function is given as
[tex]\bar{u}_A=xY_A\\Y_A=\dfrac{\bar{u}_A}{x}[/tex]
Also the YB is given as
[tex]Y_A+Y_B=100-x\\Y_B=100-x-Y_A\\Y_B=100-x-\dfrac{\bar{u}_A}{x}[/tex]
So the value of Y_A and Y_B are [tex]\dfrac{\bar{u}_A}{x}[/tex] and [tex]100-x-\dfrac{\bar{u}_A}{x}[/tex] respectively.
Part b:
Now
[tex]\bar{u}_B=xY_B\\\bar{u}_B=x(100-x-\dfrac{\bar{u}_A}{x})\\\bar{u}_B=100x-x^2-\bar{u}_A[/tex]
For the maximization
[tex]\dfrac{\partial \bar{u}_B}{\partial x}=0\\\dfrac{\partial (100x-x^2-\bar{u}_A)}{\partial x}=0\\100-2x=0\\x=100/2\\x=50[/tex]
From question 1 Y_A and Y_B are given as [tex]\dfrac{\bar{u}_A}{50}[/tex] and [tex]50-\dfrac{\bar{u}_A}{50}[/tex] respectively for maximization of Y_B
Part c:
At the Pareto efficient allocation
[tex]\dfrac{Mu_X}{Mu_{Y_A}}=\dfrac{Mu_X}{Mu_{Y_B}}[/tex]
This is simplified to
[tex]\dfrac{Y_A}{x}=\dfrac{Y_B}{x}\\Y_A=Y_B[/tex]
The condition for the Pareto efficient allocation is YA=YB
As the value of YA and YB are not equal in part 2 thus the condition is not Pareto efficient