Respuesta :
Answer:
number of moles removed = 0.6436 moles
Explanation:
given data
volume v1 = 60.6 L
volume v2 = 45.0 L
moles of Ne n1 = 2.50 moles
temperature = 25°C
solution
we will use here gas law that is express as
PV = nRT .........................1
so here we get here number of moles
so equation will be as
P1 × V1 = n1 × R × T1
and
P2 × V2 = n2 × R × T2
so from above two equation we can say at pressure and temperature constant so
[tex]\frac{V1}{V2} =\frac{n1}{n2}[/tex] ...............2
put here value we get
[tex]\frac{60.6}{45} =\frac{2.50}{n2}[/tex]
n2 = 1.856 moles
so 1.856 moles occupied when volume is 45 L
so here number of moles removed will be
number of moles removed = initial moles - final moles ...............3
put here value
number of moles removed = 2.50 - 1.856
number of moles removed = 0.6436 moles
Answer:
Explanation:
P1 = 754 torr
T1 = 25°C
n1 = 2.5 moles
V1 = 60.6 L
V2 = 45 L
Use ideal gas equation
P1 x V1 = n1 x R T1 .... (1)
Here pressure and the temperature remains constant
P1 x V2 = n2 x R x T1 ..... (2)
Divide equation (1) by (2)
V1 / V2 = n1 / n2
60.6 / 45 = 2.5 / n2
n2 = 1.856
So, the number of moles removed is 2.5 - 1.856 = 0.644
