The value of [tex]x=\frac{26}{3}, \ y=\frac{-11}{6}[/tex].
Solution:
Given equations:
7x + 2y = 57 ---------- (1)
x + 2y = 5 ---------- (2)
Subtract 2y from both sides of the equation (2).
x = 5 – 2y ---------- (3)
Substitute equation (3) in equation (1).
7(5 – 2y) + 2y = 57
35 – 14y + 2y = 57
35 – 12y = 57
Subtract 35 from both sides of the equation.
–12y = 22
Divide by 12 on both sides.
[tex]$y=\frac{-11}{6}[/tex]
Substitute y value in equation (3).
[tex]x=5-2(\frac{-11}{6} )[/tex]
[tex]x=5+\frac{11}{3}[/tex]
[tex]$x=\frac{26}{3}[/tex]
Hence the value of [tex]x=\frac{26}{3}, \ y=\frac{-11}{6}[/tex].
