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A road with a radius of 75.0 m is banked so that a car can navigate the curve at a speed of 15.5 m/s without any friction. When a car is going 22.4 m/s on this curve, what minimum coefficient of static friction is needed if the car is to navigate the curve without slipping?

Respuesta :

Answer: 0.683

Explanation: The relationship between a car moving along a curve and the frictional force is given below as

us×g = v²/r

Where us = coefficient of static friction =?, g = acceleration due to gravity = 9.8 m/s², v = 22.4 m/s and r = 75m

By substituting the parameters, we have that

us×9.8 = 22.4²/ 75

us ×9.8 = 501.76/75

us ×9.8 = 6.690

us = 6.690/9.8 = 0.683

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