Explanation:
The given data is as follows.
Velocity of bullet, [tex]c_{p}[/tex] = 814.8 m/s
Observer distance from marksman, d = 24.7 m
Let us assume that time necessary for report of rifle to reach the observer is t and will be calculated as follows.
t = [tex]\frac{24.7}{343}[/tex] (velocity in air = 343 m/s)
= 0.072 sec
Now, before the observer hears the report the distance traveled by the bullet is as follows.
[tex]d_{b} = c_{b} \times t[/tex]
= [tex]814.8 \times 0.072[/tex]
= 58.66
= 59 (approx)
Thus, we can conclude that each bullet will travel a distance of 59 m.