Respuesta :
Explanation:
According to the given situation,
work done = change in kinetic energy
As the formula of kinetic energy is as follows.
K.E = [tex]\frac{1}{2}mv^{2}[/tex]
Putting the given values into the above formula as follows.
K.E = [tex]\frac{1}{2}mv^{2}[/tex]
= [tex]\frac{1}{2} \times 5 kg \times (3 m/s)^{2}[/tex]
= 22.5 J
Also we know that,
Work done = force x distance
or, force = [tex]\frac{work}{distance}[/tex]
= [tex]\frac{22.5 J}{4 m}[/tex]
= 5.62 N
In the given case, force is friction and formula to calculate friction is as follows.
friction = [tex]\mu \times m \times g[/tex]
where, [tex]\mu[/tex] = the coefficient of friction
Putting the given values into the above formula as follows.
Friction = [tex]\mu \times m \times g[/tex]
5.62N = [tex]\mu \times 5 \times 9.8[/tex]
[tex]\mu[/tex] = 0.114
Thus, we can conclude that the coefficient of kinetic friction between the floor and the given box is 0.114.
