Answer:
1
Step-by-step explanation:
Yes, there is a solution! You first look for a common factor to factor away. Observing, you see that there is common multiple of 4, so your equation becomes [tex]4(x^2-2x+1)=0[/tex]. Dividing away the 4, we get [tex]x^2-2x+1=0[/tex]. From here, we can complete the square: [tex](x-\frac{2}{2})^2-\frac{2}{2}+1=0[/tex] which is equal to [tex](x-1)^2=0[/tex]. When x=1, both sides of the equation equal 0, so x=1.
