Respuesta :
Explanation:
The given data is as follows.
Pressure (P) = 170 torr, mass of heptane (m) = 86.7 g
First, we will calculate the number of moles as follows.
No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]
= [tex]\frac{86.7 g}{100 g/mol}[/tex]
= 0.867 mol
Now, the number of moles of [tex]CH_{3}COBr[/tex] are calculated as follows.
No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]
= [tex]\frac{125}{122.9}[/tex]
= 1.07
Therefore, mole fraction of heptane will be calculated as follows.
Mole fraction = [tex]\frac{\text{moles of heptane}}{\text{total moles}}[/tex]
= [tex]\frac{0.867}{0.867 + 1.07}[/tex]
= [tex]\frac{0.867}{1.937}[/tex]
= 0.445
Now, we will calculate the partial pressure of heptane as follows.
[tex]P_{A} = x_{A}P^{o}_{A}[/tex]
= [tex]170 \times 0.445[/tex]
= 75.65 torr
Thus, we can conclude that the partial pressure of heptane vapor above this solution is 75.65 torr.
