Answer:
0.243 moles of ammonium chloride are present in the resulting solution
Explanation:
We determine our compounds of the solution:
Solute: NH₄Cl
The solvent is water
Solution's volume: 325 mL
If we want to know, how many moles of ammonium chloride are present in the resulting solution we may just convert the solute's mass to moles.
Molar mass NH₄Cl = 53.45 g/mol
Moles of NH₄Cl = Mass of NH₄Cl / Molar mass NH₄Cl
13 g / 53.45 g/mol = 0.243 moles
Answer:
We have 0.243 moles of ammonium chloride is the solution
Explanation:
Step 1: Data given
Ammonium chloride = NH4Cl
Mass of ammonium chloride = 13.0 grams
Volume of water = 325 mL = 0.325 L
Molar mass of ammonium chloride
⇒ Molar mass N = 14.0 g/mol
⇒ Molar mass of H = 1.01 g/mol : 4*1.01 = 4.04 g/mol
⇒Molar mass of Cl = 35.45 g/mol
Molar mass NH4Cl = 53.49 g/mol
Step 2: Calculate moles ammonium chloride
Moles NH4Cl = mass NH4Cl / molar mass NH4Cl
Moles NH4Cl = 13.0 grams / 53.49 g/mol
Moles NH4Cl = 0.243 moles
We have 0.243 moles of ammonium chloride is the solution
