Respuesta :
Answer:
The sample space consists of 20 possible values.
Step-by-step explanation:
Combination is a mathematical procedure to select k items from n distinct items.
[tex]{n\choose k}=\frac{n!}{k!(n-k)!}[/tex]
Of the 6 parts, 2 of the parts are defective and 4 are acceptable.
Three parts are selected at random.
The sample space of 3 parts would consist 0, 1 or 2 defective.
- 0 defective: [tex]{4\choose 3}=4[/tex] ways to select 0 defective.
- 1 defective: [tex]{2\choose 1}{4\choose 2}=2\times6=12[/tex] ways to select 1 defective.
- 2 defective: [tex]{2\choose 2}{4\choose 1}=1\times4=4[/tex] ways to select 2 defective.
The sample space consists of = 4 + 12 + 4 = 20 possible value.
Thus, the sample space consists of 20 possible values.
The formula of the combination is used. Then the random sample space consists of a possible value is 20.
What is a random sample?
Random sampling is the method of selecting the subset from the set to make a statical inference.
A bin contains six parts. Two of the parts are defective and four are acceptable.
If three of the six parts are selected from the bin selected. Then we have
The defective part is zero, we have
[tex]$^4C_3 = 4[/tex]
The defective part is one, we have
[tex]^4C_2*^2C_1 = 6*2=12[/tex]
The defective part is two, we have
[tex]^4C_1*^2C_2 = 4*1 = 4[/tex]
The sample space consists of possible value will be
Sample space = 4 + 12 + 4 = 20
More about the random sample link is given below.
https://brainly.com/question/12719654
