The heat of fusion of dichloromethane (CH2Cl2) is 6.2 kJ/mol.
Calculate the change in entropy Δs when 345 g of dichloromethane freezes at -95.1 °C.
Be sure your answer contains a unit symbol and the correct number of significant digits.

Respuesta :

Answer : The entropy change of the dichloromethane is 142 J/K

Explanation :

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Given mass of dichloromethane = 345 g

Molar mass of dichloromethane = 84.93 g/mol

Putting values in above equation, we get:

[tex]\text{Moles of dichloromethane}=\frac{345g}{84.93g/mol}=4.06mol[/tex]

To calculate the entropy change for different phase at same temperature, we use the equation:

[tex]\Delta S=n\times \frac{\Delta H_{fusion}}{T}[/tex]

where,  

[tex]\Delta S[/tex] = Entropy change  = ?

n = moles of dichloromethane = 4.06 moles

[tex]\Delta H_{fusion}[/tex] = enthalpy of fusion = 6.2 kJ/mol = 6200 J/mol   (Conversion factor:  1 kJ = 1000 J)

T = temperature of the system = [tex]-95.1^oC=[-95.1+273]K=177.9K[/tex]

Putting values in above equation, we get:

[tex]\Delta S=\frac{4.06mol\times 6200J/mol}{177.9K}\\\\\Delta S=141.495J/K\approx 142J/K[/tex]

Hence, the entropy change of the dichloromethane is 142 J/K