Answer:
The equation is H2SO4 + 2KOH ===> K2SO4 + 2H2O
The molarity of base is 0.257 M
Explanation:
Using titration equation CAVA/CBVB = NA/NB
Where NA is the number ov mole of acid =1
Using titration equation
CAVA/CBVB = NA/NB
Where NA is the number of mole of acid = 1
NB is the number of mole of base = 2
CA is the molarity of acid =1.5M
CB is the molarity of base = to be calculated
VA is the volume of acid = 13.7 mL
VB is the volume of base = 80 mL
Substituting
1.5×80/CB×13.7 = 1/2
Therefore CB = 1.5×13.7×2/80×1
CB = 0.257 M.
