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A grocery shopper tosses a(n) 9.0 kg bag of rice into a stationary 17.4 kg grocery cart. The bag hits the cart with a horizontal speed of 5.2 m/s toward the front of the cart. What is the final speed of the cart and bag

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opudodennis

Answer:

[tex]V=1.77m/s[/tex]

Explanation:

#Using the conservation of momentum , momentum before equals momentum after([tex]p=mv)[/tex].

-Initial speed is 5.2m/s while the cart is at rest. After, the velocity will be of a combined(bag+cart) mass.

Hence:

[tex]9.0\times 5.2+17.4\times 0=(9+17.4)V\\\\V=\frac{9\times5.2}{9+17.4}\\\\=1.77m/s\\[/tex]

Hence, the final velocity of the cart and bag is 1.77m/s

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