contestada

7. Andrew has map of a hidden treasure. He travels 5
meters 90°north, then he moves 13 meters 45° east
where treasure is hidden. Find the distance between
Andrew's initial location to the hidden treasure.

Respuesta :

Answer:

[tex]d=16.9\ m[/tex]

Step-by-step explanation:

Let

[tex]A(0,0)[/tex] -----> Andrew's initial location

we know that

1) He travels 5  meters 90°north

At this moment Andrew's location is

[tex]B(0,0+5)\\B(0,5)[/tex]

2) He moves 13 meters 45° east

At this moment Andrew's location is

[tex]C(0+13cos(45^o),5+13sin(45^o))[/tex]

[tex]C(0+13\frac{\sqrt{2}}{2},5+13\frac{\sqrt{2}}{2})[/tex]

[tex]C(13\frac{\sqrt{2}}{2},5+13\frac{\sqrt{2}}{2})[/tex]

3) Find the distance between  Andrew's initial location to the hidden treasure.

Find the distance between point A and point C

the formula to calculate the distance between two points is equal to

[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]

we have

[tex]A(0,0)[/tex]

[tex]C(13\frac{\sqrt{2}}{2},5+13\frac{\sqrt{2}}{2})[/tex]

substitute the values

[tex]d=\sqrt{(5+13\frac{\sqrt{2}}{2}-0)^{2}+(13\frac{\sqrt{2}}{2}-0)^{2}}[/tex]

[tex]d=16.9\ m[/tex]