Answer:
Explanation:
Given
mass of motor [tex]m=51\ kg[/tex]
Area of piston [tex]A_1=0.25\ m^2[/tex]
Area of Piston 2 is [tex]A_2=84\ cm^2[/tex]
Weight of motor [tex]F_1=m\cdot g=51\times 9.8[/tex]
[tex]F_1=499.8\ N[/tex]
If [tex]F_2[/tex] is the force applied on the 2 nd piston
According Pascal law Pressure at both the ends are equal
[tex]\frac{F_1}{A_1}=\frac{F_2}{A_2}[/tex]
[tex]\frac{499.8}{0.25}=\frac{F_2}{84}[/tex]
[tex]F_2=167.93\ kN[/tex]
[tex]F_2=167.93\times 10^3\ N[/tex]
