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Hello,
Answer B 6*6 in²
(x+10)²=256
==>(x+10)²-16²=0
==>(x+10-16)(x+10+16)=0
==>x=6 or x=-26 (excluded)
Answer B 6*6 in²
(x+10)²=256
==>(x+10)²-16²=0
==>(x+10-16)(x+10+16)=0
==>x=6 or x=-26 (excluded)
Answer:
The original dimension was 6 inches by 6 inches.
Step-by-step explanation:
'x' represents the side measure of the original square photo.
Given is that Shayna enlarged a square photo by adding 10 inches to each side so it could be seen on a large poster.
The given equation is:
[tex](x+10)^{2} =256[/tex]
Solving for 'x' as x was the original dimension in which 10 was added.
[tex]x^{2} +20x+100=256[/tex]
[tex]x^{2} +20x-156=0[/tex]
[tex]x^{2} +26x-6x-156=0[/tex]
[tex]x(x+26)-6(x+26)=0[/tex]
[tex](x+26)(x-6)=0[/tex]
[tex]x=-26[/tex] and [tex]x=6[/tex]
Neglecting the negative value as dimension cannot be negative.
So, we have x=6 inch
Therefore, the original dimension was 6 inches by 6 inches.