shayna enlarged a square photo by adding 10 inches to each side so it could be seen on a large poster. the area of the enlarged photo is 256 square inches. in the equation (x 10)2 = 256, x represents the side measure of the original square photo. what were the dimensions of the original photo? 4 inches by 4 inches 6 inches by 6 inches 10 inches by 10 inches 12 inches by 12 inches

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caylus
Hello,

Answer B 6*6 in²

(x+10)²=256
==>(x+10)²-16²=0
==>(x+10-16)(x+10+16)=0
==>x=6 or x=-26 (excluded)


Answer:

The original dimension was 6 inches by 6 inches.

Step-by-step explanation:

'x' represents the side measure of the original square photo.

Given is that Shayna enlarged a square photo by adding 10 inches to each side so it could be seen on a large poster.

The given equation is:

[tex](x+10)^{2} =256[/tex]

Solving for 'x' as x was the original dimension in which 10 was added.

[tex]x^{2} +20x+100=256[/tex]

[tex]x^{2} +20x-156=0[/tex]

[tex]x^{2} +26x-6x-156=0[/tex]

[tex]x(x+26)-6(x+26)=0[/tex]

[tex](x+26)(x-6)=0[/tex]

[tex]x=-26[/tex] and [tex]x=6[/tex]

Neglecting the negative value as dimension cannot be negative.

So, we have x=6 inch

Therefore, the original dimension was 6 inches by 6 inches.