Complete Question
The complete question is shown on the first uploaded image
Answer:
The time t required is [tex]t= 2.73 *10^{-8} sec[/tex]
Explanation:
When this proton move into the magnetic field region the magnetic field would cause it to move in a clockwise direction
The force which it would feel inside the field is mathematically denoted as follows
[tex]F = qvB[/tex]
And this is the same thing as the force which keeps it around the circle without spiraling off and this is also know as centripetal force and it is mathematically
[tex]F_c = \frac{mv^2}{r}[/tex]
Since the two force are equal we can equate the formulas
[tex]qvB = \frac{mv^2}{r}[/tex]
making r the subject of the formula
[tex]r = \frac{mv}{qB} = \frac{(1.67*10^{-27)(1*10^6)}}{(1.60*10^{-19)(1.2)}} = 8.7*10^{-3} m[/tex]
Now mathematically the total distance traveled is
[tex]S = \pi r[/tex]
Since [tex]Time = \frac{distance }{velocity}[/tex]
= [tex]\frac{\pi r}{v} =\frac{(3.142 *8.7*10^{-3})}{1*10^6} = 2.73 *10^{-8} sec[/tex]
