Answer:
The magnitude of the torque on the wire loop is 3.68 Nm.
Explanation:
Given that,
Magnetic field = 3.5 T
Suppose, A circular wire loop with a radius of 62.7 cm lies flat in the horizontal x-y plane and contains a current of 852 mA that runs counter-clockwise in the wire loop when viewed from above.
We need to calculate the area
Using formula of area
[tex]A=\pi r^2[/tex]
Put the value into the formula
[tex]A=\pi\times(62.7\times10^{-2})^2[/tex]
[tex]A=1.235\ m^2[/tex]
We need to calculate the magnitude of the torque on the wire loop
Using formula of magnetic field
[tex]\tau=NIAB\sin90[/tex]
Put the value into the formula
[tex]\tau=1\times852\times10^{-3}\times1.235\times3.5\times1[/tex]
[tex]\tau=3.68\ Nm[/tex]
Hence, The magnitude of the torque on the wire loop is 3.68 Nm.