Answer:
[tex]\Delta t = 3.5\,s[/tex]
Explanation:
Time require per unit is directly proportional to need radio of curvature. In other words:
[tex]\Delta t \propto \rho[/tex]
The time requiered to bend the straight wire into a circule of radius 7 is estimated by simple rule of three:
[tex]\Delta t = \frac{7\,u}{2\,u}\cdot (1\,s)[/tex]
[tex]\Delta t = 3.5\,s[/tex]
Answer:
21.994 seconds
Explanation:
l = length of the wire
r = radius of bend = 7
Perimeter of the bend = perimeter of a circle = 2πr
Perimeter = dl = 2 * π * 7 = 14π
dl = 14π ...............(1)
Rate of bend = dl/dt =2 units/sec
dl = 2 dt...............(2)
Equate (1) and (2)
2 dt = 14π
dt = 14π/2
dt = 7π seconds
dt = 21.994 seconds
