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If 0.25 mol of HClO2 is added to enough water to prepare a 0.25 M HClO2 aqueous solution, what is the concentration of H3O+(aq) at equilibrium? At this temperature, Kc is 0.15 for the equation, HClO2(aq) + H2O(l) ⇌ H3O+(aq) + ClO2−(aq)

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Answer:

The concentration of H3O+= 0.15M

Explanation:

From The equation of reaction

HClO2(aq) + H2O(l) ⇌ H3O+(aq) + ClO2−(aq)

0.25mol HClO2(aq) 0.25mol producesClO2−(aq) and x-mol of H3O+

Using Kc = [H3O+][ClO2-]/[HClO2]

0.15= 0.25*x/0.25

Simplify

x=0.15M

The concentration of H3O+= 0.15M

Calculation of the concentration;

Since 0.25 mol of HClO2 is added to enough water to prepare a 0.25 M HClO2 aqueous solution

Now

The equation of the reaction is

HClO2(aq) + H2O(l) ⇌ H3O+(aq) + ClO2−(aq)

Now

Kc = [H3O+][ClO2-]/[HClO2]

0.15= 0.25*x/0.25

x=0.15M

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