Answer:
option B
Explanation:
Given,
Refractive index of the glass, n₂ = 1.50
Refractive index of plastic, n₁ = 1.30
critical angle = ?
[tex]\theta_{critical}=\sin^{-1} (\dfrac{n_1}{n_2})[/tex]
n₁ is the refractive index of the rare medium
n₂ is the refractive index of the denser medium.
[tex]\theta_{critical}=\sin^{-1} (\dfrac{1.30}{1.50})[/tex]
[tex]\theta_{critical}=\sin^{-1} (0.8667)[/tex]
[tex]\theta_{critical}=60.1^\circ[/tex]
The correct answer is option B
