Answer:
Q = 3.254 x 10⁻¹⁰ C.
Explanation:
Given,
Potential, V = 9 V
Radius of circular plat re = 0.057 m
Air gap, s = 2.5 mm
Charge on the positive plate = ?
We know,
Q = C V
and
[tex]C = \epsilon_o \dfrac{A}{s}[/tex]
[tex]C = (8.854\times 10^{-12}) \dfrac{\pi r^2}{0.0025}[/tex]
[tex]C = (8.854\times 10^{-12}) \dfrac{\pi \times 0.057^2}{0.0025}[/tex]
C = 36.15 x 10⁻¹² F
now,
Q = 36.15 x 10⁻¹² x 9
Q = 3.254 x 10⁻¹⁰ C.
Hence, the charge on the positive plate is equal to Q = 3.254 x 10⁻¹⁰ C.
