Putting the Tiles in Order;

A university is conducting a survey to study the number of hours students sleep at night during exam week. A sample of 20 students was drawn, and these responses were obtained: 6.5, 5, 8, 5.5, 7, 4, 4.5, 5, 6, 5.5, 4, 7.5, 6, 7, 8, 5, 6, 6.5, 6.5, 5. The standard deviation of the population mean is 2 hours.

Arrange the steps in the correct sequence to find the range in which 95% of the sample mean occurs.

Tiles are:
1. The range in which 95% of the sample mean occurs
= 5.93 + 2 × 0.45 and 5.93 − 2 × 0.45
= 6.83 hours and 5.03 hours.

2. The sample mean is /u = 118.5/20=5.93

3. Calculate the standard deviation.

4. The 20 students' total number of study hours
is 118.5 hours.

5. The standard error of the mean of the sample is sigma/sqrt n = 2/sqrt 20 = 0.45

6. The range in which 95% of the sample mean occurs is /u +- 2 X sigma/ sqrt n.

Only need 5 steps
.

It is given that A sample of 20 students was drawn, and these responses were obtained: 6.5, 5, 8, 5.5, 7, 4, 4.5, 5, 6, 5.5, 4, 7.5, 6, 7, 8, 5, 6, 6.5, 6.5, 5. The standard deviation of the population mean is 2 hours.

The following steps are used to find the range:

Step 1. (4) The 20 students' total number of study hours

is 118.5 hours.

Step 2. (2) The sample mean is:

[tex]{\mu}=\frac{118.5}{20}=5.93[/tex]

Step 3. (5) The standard error of the mean of the sample is:

[tex]\frac{\sigma}{\sqrt{n}}=\frac{2}{\sqrt{20}}=0.45[/tex]

Step 4. (6) The range in which 95% of the sample mean occurs is:

[tex]{\mu}+2{\times}\frac{\sigma}{\sqrt{n}}[/tex].

Step 5. (1)The range in which 95% of the sample mean occurs

=[tex]5.93+2{\times}0.45 and 5.93-2{\times}0.45[/tex]

=[tex]6.83 hours and 5.03 hours.[/tex]

wifilethbridge wifilethbridge · Answer 2 · 2019-05-13T09:26:45+02:00

Answer:

Step 1 = Tile 4

Step 2 = Tile 2

Step 3 = Tile 5

Step 4 = Tile 6

Step 5 = Tile 1

Step-by-step explanation:

We are given A sample of 20 students was drawn, and these responses were obtained: 6.5, 5, 8, 5.5, 7, 4, 4.5, 5, 6, 5.5, 4, 7.5, 6, 7, 8, 5, 6, 6.5, 6.5, 5.

So, First Find the sum of the number of hours students sleep at night

So, 6.5+5+ 8+ 5.5+ 7+4+ 4.5+ 5+ 6+ 5.5+ 4+ 7.5+ 6+7+8+5+6+6.5+6.5+ 5= 118.5

So, The 20 students' total number of study hours is 118.5 hours.

So, Step 1 = Tile 4

Now find the sample mean : [tex]\mu = \frac{\tetx{Sum of hours}}{\text{Total no. of students}}[/tex]

So, [tex]\mu = \frac{1178.5}{20}=5.93[/tex]

So, Step 2 = Tile 2

Now standard deviation is given S.d. = 2

Now find the The standard error of the mean of the sample

Formula : [tex]\frac{\sigma}{\sqrt{n}}[/tex]

So, standard error = [tex]\frac{2}{\sqrt{20}}=0.45[/tex]

So, Step 3 = Tile 5

Now formula of Range in which 95% of the sample mean occurs= [tex]\mu \pm 2 \times \frac{\sigma}{\sqrt{n}}[/tex]

So, Step 4 = Tile 6

Now substitute the values in formula

So, [tex]5.93\pm 2 \times \frac{2}{\sqrt{20}}[/tex]

[tex]5.93\pm 2 \times 0.45[/tex]

So, Step 5 = Tile 1

1. The range in which 95% of the sample mean occurs

= 5.93 + 2 × 0.45 and 5.93 − 2 × 0.45

= 6.83 hours and 5.03 hours.