Respuesta :

The graph of y = 1/2(x + 4)^2 is a shrink of y = (x - 1)^2 - 3
The vertex of the graph of y = 1/2(x + 4)^2 is 5 units to the left and 3 units up of the vertex of the graph of y = (x - 1)^2 - 3.

Answer:

Vertical stretch and compression:

Given a function f(x) , a new function g(x) =a f(x), where a is the constant, is a vertical stretch or vertical compression of the function f(x).

  • if 0<a<1 , then the graph will be compressed
  • if a > 1 the graph will be stretched .
  • if a<0, then there will be combination of a vertical stretch or compression with a vertical reflection.

In general if a function is shifted  a  units right and  b  units down we can summaries this as:

f(x) is shifted a units right and b units down [tex]\rightarrow[/tex] f(x-a) -b

Given the function: [tex]y = \frac{1}{2}(x+4)^2[/tex]

Now, replace y with [tex]2 y[/tex] results in a vertical stretch by a factor of 2.


⇒ [tex]y = (x+4)^2[/tex]

Then, by definition of above;

now, shift function [tex]y = (x+4)^2[/tex]  as 5 units right and 3 units down we have;

[tex]y = (x+4-5)^2 -3[/tex] or

[tex]y = (x-1)^2 -3[/tex]

Therefore, the transformation from the graph [tex]y = \frac{1}{2}(x+4)^2[/tex] is vertically stretch by a factor 2 and it is shift to 5 units right and 3 units down we have then, [tex]y = (x-1)^2 -3[/tex]

Also, you can see the graph shown below;

Ver imagen OrethaWilkison