The equilibrium expression is Equilibrium constant = [tex]\frac{concentration of product }{concentration of reactant}[/tex]
Kc or equilibrium constant for this reaction is 0. 55 x [tex]10^{2}[/tex]
Explanation:
Br2(g) + Cl2(g) ⇌ 2BrCl(g)
Equilibrium constant = [tex]\frac{concentration of product }{concentration of reactant}[/tex]
Kc =[tex][BrCl]^{2}[/tex] [tex]\frac{[BrCl[2}{[Br]2[Cl]2}[/tex] equation 1
the concentration of diatoms will be divided by 2
1.3 x 10^-2 is concentration of chlorine
0.45 x 10^-2 is concentration of bromine
1.6 ×10−2 is concentration of BrCl2
Putting the values in equation 1 to calculate equilibrium constant.
Kc= [tex]\frac{[1.6 ×10−2]}{[0.45 x 10^-2] [1.6 ×10−2]}[/tex]
Kc = [tex]\frac{ 1.6 ×10−2}{2.9 x 10-4}[/tex]
Kc= 0.55 x 10^2
equilibrium constant for this reaction is 0.55 x [tex]10^{2}[/tex]
the molar concentration or partial pressure of the gases is taken to find the equilibrium constant.
