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Compressed air is used to fire a 50g ball vertically upward from a1.0m-tall tube. The air exerts an upward force of 2.0N on the ballas long as it is in the tube.
Q: How high does the ball go above the top of the tube?

Respuesta :

The maximum height attain by ball is [tex]4.07[/tex] meters.

Equation of motion :

The maximum height attain by ball is,

                      [tex]h=\frac{v^{2} }{2g}[/tex]

Given that, mass of ball [tex]m=50g=0.05kg[/tex] and force [tex]F=2N[/tex]

  • Acceleration,[tex]a=\frac{F}{m}[/tex]

                   [tex]a=\frac{2}{0.05}=40m/s^{2}[/tex]

  • The velocity of ball is given by,

             [tex]v=\sqrt{2ay}=\sqrt{2*40*1}=8.94m/s[/tex]

Value of [tex]g=9.8m/s^{2}[/tex]

The maximum height attain by ball is,

                    [tex]h=\frac{(8.94)^{2} }{2*9.8}\\ \\h=4.07m[/tex]

Learn more about the velocity here:

https://brainly.com/question/6504879

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