Could someone please help me with this problem

Answer:
a = -1 , b = 4 , c = 3 , d = 1
Step-by-step explanation:
Given:
[tex](-xy)^3 (xz) =ax^by^cz^d[/tex]
The right hand side = (-xy)³ (xz) = (-1)³ x³ y³ x z = (-1) x⁴ y³ z
Comparing the right hand side with the left hand side
∴ a = -1
∴ b = 4
∴ c = 3
∴ d = 1
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The general rules of exponent:
[tex]1) \ a^m * a^n = a^{m+n}\\2) \ a^m / a^n = a^{m-n}\\3) (-1)^m = 1 \ (if \ m \ is \ +) and \ = \ -1 \ (if \ m \ is \ -)[/tex]