Respuesta :
The exact probability that the blue ball is drawn first and the red ball is drawn second is [tex]\frac{1}{132}[/tex]
Solution:
The probability of an event is given as:
[tex]Probability = \frac{ \text{ number of favorable outcomes }}{ \text{ total number of possible outcomes }}[/tex]
Given that,
There are 12 balls in a bag
One is blue and one is red
Favorable outcome = blue ball is drawn first
Favorable outcome = 1
Therefore,
[tex]Probability = \frac{1}{12}[/tex]
Now, without replacement, red ball is drawn second
Therefore,
Total possible outcomes = 12 - 1 = 11
[tex]Probability = \frac{1}{11}[/tex]
What is the exact probability that the blue ball is drawn first and the red ball is drawn second?
[tex]Total\ probability = \frac{1}{12} \times \frac{1}{11} = \frac{1}{132}[/tex]
Thus the exact probability that the blue ball is drawn first and the red ball is drawn second is [tex]\frac{1}{132}[/tex]
