Answer:
The work input during this process is -742 kJ
Explanation:
Given;
Initial temperature of nitrogen T₁ = 250 K
final temperature of nitrogen T₂ = 450 K
mass of nitrogen, m = 5 kg
[tex]PV^{1.4} = constant[/tex]
The work input during the process is calculated as;
[tex]W = \frac{m*R(T_2-T_1)}{1-n}[/tex]
where;
R is gas constant = 0.2968 kJ/kgK
substitute given values in above equation.
[tex]W = \frac{m*R(T_2-T_1)}{1-n} = \frac{5*0.2968(450-250)}{1-1.4} = -742 \ kJ[/tex]
Therefore, the work input during this process is -742 kJ
