The mean of this discrete random variable is 7.96
Solution:
Given that,
x 4 6 9 11 15
P(x) 0.20 0.34 0.15 0.22 0.09
Mean is given as:
[tex]\mu_{x}=\sum[x \times P(x)][/tex]
Therefore,
[tex]\mu_{x} = (4 \times 0.20) + (6 \times 0.34 ) + (9 \times 0.15 ) + (11 \times 0.22 ) + (15 \times 0.09)\\\\Simplify\\\\\mu_{x} = 0.8 + 2.04 + 1.35 + 2.42 + 1.35\\\\\mu_{x} = 7.96[/tex]
Thus, mean of this discrete random variable is 7.96