Answer:
The answer to the question is;
Red= 0.6, White= 0.4
Step-by-step explanation:
To solve the question, we note that an homozygous gene has two allele of the same type while an heterozygous gene has two different allele in its gene
Therefore we have
Let the red allele be R,
Let the white allele be W,
Therefore we have the heterozygous given by RW while
The red short horned cattle are RR and
the white cattle carry the genes WW
Since the population A consists of 36 % red, 16 % white, and 48 % roan,
we have RR = 36 %
WW = 16 %
RW = 48 %
That is there are in 100 % 36 RR (2 Reds) , 16 WW (2 Whites) and 48 RW (48 each Red and White)
Total Red allele = 2*36 + 48 = 120
and total White allele = 2*16 + 48 = 80
That is the frequency of the Red allele = 120/(120+80) = 120/200
= 0.6
the frequency of the White allele = 80/(120+80) = 80/200 = 0.4
