Answer:
54.54g
Explanation:
First, let us obtain the number of mole of Barium chlorate, Ba(ClO3)2 in the solution. This is illustrated below:
Volume = 345mL = 345/1000 = 0.345L
Molarity = 0.520mol/L
Mole =?
Molarity = mole /Volume
Mole = Molarity x Volume
Mole = 0.520 x 0.345
Mole = 0.1794mole
Now, we can easily find the mass of the Barium chlorate. This is illustrated below:
Molar Mass of Ba(ClO3)2 = 137 + 2[35.5 + (16x3)] = 137 +2[35.5 + 48] = 137 + 2[83.5] = 137 + 167 = 304g/mol
Number of mole of Ba(ClO3)2 = 0.1794mole
Mass =?
Mass = number of mole x Molar Mass
Mass of Ba(ClO3)2 = 0.1794 x 304
Mass of Ba(ClO3)2 = 54.54g
Answer:
The mass of barium chlorate is 54.6 grams
Explanation:
Step 1: Data given
Barium chlorate = Ba(ClO3)2
Volume of the barium chlorate solution = 345.0 mL = 0.345 L
Concentration of the barium chlorate solution = 0.520 M
Molar mass of barium chlorate = 304.23 g/mol
Step 2: Calculate moles Ba(ClO3)2
Moles Ba(ClO3)2 = volume of Ba(ClO3)2 solution * concentration of Ba(ClO3)2
Moles Ba(ClO3)2 = 0.345 L * 0.520 M
Moles Ba(ClO3)2 = 0.1794 moles
Step 3: calculate mass of Ba(ClO3)2
Mass Ba(ClO3)2 = moles Ba(ClO3)2 * molar mass Ba(ClO3)2
Mass Ba(ClO3)2 = 0.1794 moles * 304.23 g/mol
Mass Ba(ClO3)2 = 54.6 grams
The mass of barium chlorate is 54.6 grams
