John wants to invite around 78000 college students to a tournament. Which of the following sets of college student populations has a sum closest to 78000.

Set A has a college student population with the sum closest to 78,000.
Step-by-step explanation:
Step 1:
First, we need to determine the sums of college student populations.
Set 1; [tex]18,432+32,761+27,390 = 78,583.[/tex]
Set 2; [tex]15,791+47,318+27,522 = 90,631,[/tex]
Set 3; [tex]22,109+38,569+32,780 = 93,458,[/tex]
Set 4; [tex]27,420 +47,338+22,183 = 96,941.[/tex]
Now we determine the difference in populations between the given sets and 78,000.
Set 1; [tex]78,583 - 78,000 = 583,[/tex]
Set 2; [tex]90,631-78,000 = 12,631,[/tex]
Set 3; [tex]93,458-78,000 = 15,458,[/tex]
Set 4; [tex]96,941-78,000=18,941.[/tex]
Set 1 has the minimum difference of all the sets, so it is the answer.
Answer: A 18 + 33 + 27 ~ 50 + 27 ~ 77 the closer
B 15+ 47 + 27 ~ 60 + 27 ~87
C 22 + 39 +32 ~ 62 + 32 ~ 94
D